编程到什么水平才可以写出一个游戏辅助？

要做有些辅助，首先你得明白游戏辅助实现的原理，才能对症下药。

这里我大概说一下游戏辅助的几个类。

简单说这么多吧，你要学习作游戏辅助的话，道路还是很漫长的。

当然了，你要嫌慢的话可以过来跟着我学，15年技术沉淀

public void calc() {

articleWordMap = new HashMap();

//读取文章

calcFreauency(articleWordMap,new File("/home/geekgao/朴素贝叶斯/500trainblogxml/positiveout/1377331000713.txt"));

keepEmotionWord(articleWordMap);

double allBackPos = 1;

double allBackNeg = 1;

double allBackUns = 1;

Set word = articleWordMap.keySet();

for (Iterator it = word.iterator();it.hasNext();) {

String tmp = (String)it.next();

double back;

if (backPositive.containsKey(tmp)) {

back = backPositive.get(tmp);

allBackPos = Math.pow(back,articleWordMap.get(tmp)) * allBackPos;

}

if (backNegative.containsKey(tmp)) {

back = backNegative.get(tmp);

allBackNeg= Math.pow(back,articleWordMap.get(tmp)) * allBackNeg;

}

if (backUnsure.containsKey(tmp)) {

back = backUnsure.get(tmp);

allBackUns = Math.pow(back,articleWordMap.get(tmp)) * allBackUns;

}

}

double resultPositive;

double resultNegative;

double resultUnsure;

resultPositive = priorPositive * allBackPos;

resultNegative = priorNegative * allBackNeg;

resultUnsure = priorUnsure * allBackUns;

System.out.println("积极：" + resultPositive);

System.out.println("消极：" + resultNegative);

System.out.println("不确定：" + resultUnsure);

}

//解析出文章中的词语，并且映射上频数

public void calcFreauency(Map wordMap,File article) {

try {

//取得dom4j的解析器

SAXReader reader = new SAXReader();

//取得代表文档的Document对象

Document document = reader.read(article);

//取得根结点

Element root = document.getRootElement();//取得根节点

List list1 = root.elements();//取得的子节点

List sentence_list = ((Element)list1.get(0)).elements();//下的集合

List tok_list;//下的集合

//遍历节点

for (int i = 0; i < sentence_list.size(); i++) {

tok_list = ((Element)sentence_list.get(i)).elements();//获得每个sentence的tok集合

for (int j = 0;j < tok_list.size();j++) {

setWordMap((Element)tok_list.get(j),wordMap);

}

}

} catch (DocumentException e) {

e.printStackTrace();

}

}

public void setWordMap(Element tok,Map wordMap) {

String type,text;

List list;

if (!(tok.getName().equals("tok"))) {//如果不是tok节点，那么就不用处理了

return ;

}